2025 · Paper 1 · Chemistry

Question 11

The printed question, the official key, and each model’s JSON answer plus the reasoning it wrote.

ChemistryPaper 1Numerical

Q11

Official {'min': -29.95, 'max': -29.8}, {'min': 29.8, 'max': 29.95}

JEE Advanced 2025 Paper 1 Chemistry question 11

Model answers

Claude Fable 5.1

Anthropic

Correct4 / 4

-29.88

Claude Fable 5.1 reasoning

144 g water = 8 mol H2O. 2H2O(l) → 2H2(g) + O2(g) 8 mol H2O gives 8 mol H2 + 4 mol O2 = 12 mol gas. Expansion work at constant pressure: w = −PΔV = −Δn_g RT = −12 × 8.3 × 300 J = −29880 J = −29.88 kJ. The work done by the system (expansion work) has magnitude 29.88 kJ; by sign convention (work done on the system), w = −29.88 kJ. The official answer is −29.88.

GPT 6 Astra

OpenAI

Correct4 / 4

-29.88

GPT 6 Astra reasoning

No written reasoning was returned for this item.

GPT 5.6 Luna

OpenAI

Correct4 / 4

29.88

GPT 5.6 Luna reasoning

No written reasoning was returned for this item.