2025 · Paper 1 · Physics

Question 3

The printed question, the official key, and each model’s JSON answer plus the reasoning it wrote.

PhysicsPaper 1Single correct

Q03

Official A

JEE Advanced 2025 Paper 1 Physics question 3

Model answers

Claude Fable 5.1

Anthropic

Correct3 / 3

A

Claude Fable 5.1 reasoning

**Setting up the flux** The loop rotates from the XZ plane into the region y ≥ 0 (clockwise as viewed from +X takes the loop from +Z toward +Y). Hence: - For 0 ≤ ωt ≤ π, the loop is in y ≥ 0 where the field exists. - For π ≤ ωt ≤ 2π, the loop is in y < 0 where B = 0, so the emf is zero. While in the field, the loop's normal makes angle ωt with the Z‑axis, so Φ = B₀ cos(ωt) · A · cos(ωt) = B₀A cos²(ωt) V = −dΦ/dt = B₀Aω · 2 sin(ωt)cos(ωt) = B₀Aω sin(2ωt) So the emf is a sinusoid of angular frequency 2ω (one full cycle between t = 0 and π/ω), then zero from π/ω to 2π/ω, then repeats. This matches plot (A).

GPT 6 Astra

OpenAI

Correct3 / 3

A

GPT 6 Astra reasoning

No written reasoning was returned for this item.

GPT 5.6 Luna

OpenAI

Correct3 / 3

A

GPT 5.6 Luna reasoning

No written reasoning was returned for this item.