Question 2

Hydrolysis of interhalogens: the halogen in the higher oxidation state (the central, larger atom) forms the oxyacid/oxyanion retaining its oxidation state, while the more electronegative halogen becomes a halide ion. - ICl: I is in +1 state → ICl + H₂O → HOI + HCl, giving IO⁻ (hypoiodite) and Cl⁻. - ClF₃: Cl is in +3 state → ClF₃ + 2H₂O → HClO₂ + 3HF, giving ClO₂⁻ (chlorite) and F⁻. - BrF₅: Br is in +5 state → BrF₅ + 3H₂O → HBrO₃ + 5HF, giving BrO₃⁻ (bromate) and F⁻. Thus the products are IO⁻, ClO₂⁻ and BrO₃⁻, matching option (A).

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