2025 · Paper 2 · Chemistry

Question 11

The printed question, the official key, and each model’s JSON answer plus the reasoning it wrote.

ChemistryPaper 2Numerical

Q11

Official 15.5 – 16.5

JEE Advanced 2025 Paper 2 Chemistry question 11

Model answers

Claude Fable 5.1

Anthropic

Correct4 / 4

16

Claude Fable 5.1 reasoning

**Freundlich isotherm:** x/m = k·C^(1/n), so log(x/m) = log k + (1/n) log C. Using the two data points: (1/n) = [log 10 − log 4] / [log 16 − log 10] = (1 − 0.6)/(1.2 − 1) = 0.4/0.2 = 2 So x/m = k·C². From C = 10, x/m = 4: k = 4/100 = 0.04. At C = 20 mg g⁻¹: x/m = 0.04 × 400 = **16 mg g⁻¹**

GPT 6 Astra

OpenAI

Correct4 / 4

16

GPT 6 Astra reasoning

No written reasoning was returned for this item.

GPT 5.6 Luna

OpenAI

Correct4 / 4

16

GPT 5.6 Luna reasoning

No written reasoning was returned for this item.