2025 · Paper 2 · Chemistry

Question 15

The printed question, the official key, and each model’s JSON answer plus the reasoning it wrote.

ChemistryPaper 2Numerical

Q15

Official 7.5 – 7.8

JEE Advanced 2025 Paper 2 Chemistry question 15

Model answers

Claude Fable 5.1

Anthropic

Correct4 / 4

7.73

Claude Fable 5.1 reasoning

[Mn(Br)₆]³⁻: Mn is in +3 oxidation state, d⁴. Br⁻ is a weak field ligand → high spin, t₂g³ e_g¹, 4 unpaired electrons. μ = √(4×6) = √24 ≈ 4.90 B.M. [Mn(CN)₆]³⁻: Mn³⁺, d⁴. CN⁻ is a strong field ligand → low spin, t₂g⁴, 2 unpaired electrons. μ = √(2×4) = √8 ≈ 2.83 B.M. Sum = 4.90 + 2.83 = 7.73 B.M.

GPT 6 Astra

OpenAI

Correct4 / 4

7.73

GPT 6 Astra reasoning

No written reasoning was returned for this item.

GPT 5.6 Luna

OpenAI

Correct4 / 4

7.73

GPT 5.6 Luna reasoning

No written reasoning was returned for this item.