2025 · Paper 2 · Mathematics

Question 13

The printed question, the official key, and each model’s JSON answer plus the reasoning it wrote.

MathematicsPaper 2Numerical

Q13

Official -2

JEE Advanced 2025 Paper 2 Mathematics question 13

Model answers

Claude Fable 5.1

Anthropic

Correct4 / 4

-2

Claude Fable 5.1 reasoning

ω = e^{2πi/3}. -ω = e^{iπ}e^{2πi/3} = e^{i5π/3} = e^{-iπ/3}. Let ζ = -ω = e^{-iπ/3}, a primitive 6th root of unity. Sum_{n=1}^{2025} ζ^n. Since ζ^6 = 1 and sum over full period is 0, 2025 = 6·337 + 3, so sum = ζ + ζ^2 + ζ^3 = e^{-iπ/3} + e^{-2iπ/3} + e^{-iπ} = (1/2 - i√3/2) + (-1/2 - i√3/2) + (-1) = -1 - i√3. arg(-1 - i√3) = -2π/3. So α = -2π/3, 3α/π = -2.

GPT 6 Astra

OpenAI

Correct4 / 4

-2

GPT 6 Astra reasoning

No written reasoning was returned for this item.

GPT 5.6 Luna

OpenAI

Correct4 / 4

-2

GPT 5.6 Luna reasoning

No written reasoning was returned for this item.