Middle term(s) in \((x+a)^n\) for JEE

Formula

\[\text{For even }n,\; T_{\frac{n}{2}+1}={n\choose \frac{n}{2}}x^{\frac{n}{2}}a^{\frac{n}{2}}\]

Variables: \(n\) is an even positive integer.

Direct evaluation of middle term in standard binomial expansion.