Intersection of line and circle centered at origin for JEE

Formula

\(x^2+y^2=a^2,\ y=mx+c\Rightarrow (1+m^2)x^2+2mcx+(c^2-a^2)=0\)

Variables: Circle radius \(a\), line slope \(m\), intercept \(c\).

Finding coordinates of intersection points, secant/tangent conditions.