Bayes' theorem for JEE

Formula

\(P(B_j\mid A)=\frac{P(B_j)P(A\mid B_j)}{\sum_{i=1}^{n}P(B_i)P(A\mid B_i)}\)

Variables: \(B_1,B_2,\dots,B_n\): partition events, \(A\): observed event.

Conditions: \(P(A)>0\), \(P(B_i)>0\).

Posterior probability; source/urn/defect problems.