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Trigonometry Mock Test for JEE

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Q1MathsUnit 14: Trigonometry
Assertion Consider f(x)=sin⁡−1(sec⁡(tan⁡−1x)+\boldsymbol{f}(\boldsymbol{x})=\sin ^{-1}\left(\sec \left(\tan ^{-1} \boldsymbol{x}\right)+\right. cos⁡−1(cosec⁡(cot⁡−1x)\cos ^{-1}\left(\operatorname{cosec}\left(\cot ^{-1} x\right)\right. Statement-1: Domain of f(x)f(x) is a singleton. Reason Statement-2: Range of the function f(x)\boldsymbol{f}(\boldsymbol{x}) is a singleton.
Q2MathsUnit 14: Trigonometry
The number of real solutions of the equation tan⁡−1x(x+1)+\tan ^{-1} \sqrt{x(x+1)}+ sin⁡−1x2+x+1=π2\sin ^{-1} \sqrt{x^{2}+x+1}=\frac{\pi}{2} is
Q3MathsUnit 14: Trigonometry
A=cos⁡200cos⁡400cos⁡600cos⁡800\mathbf{A}=\cos 20^{0} \cos 40^{0} \cos 60^{0} \cos 80^{0} B=cos⁡60cos⁡420cos⁡660cos⁡780\mathbf{B}=\cos 6^{0} \cos 42^{0} \cos 66^{0} \cos 78^{0} C=cos⁡360cos⁡720cos⁡1080cos⁡1440\mathbf{C}=\cos \mathbf{3} \mathbf{6}^{\mathbf{0}} \cos \mathbf{7} \mathbf{2}^{\mathbf{0}} \cos \mathbf{1 0} \mathbf{8}^{\mathbf{0}} \cos \mathbf{1} \mathbf{4} \mathbf{4}^{\mathbf{0}}
Q4MathsUnit 14: Trigonometry
The measures of the angles of a triangle are in the ratio 4:5:9.4: 5: 9 . The triangle is:
Q5MathsUnit 14: Trigonometry
If value of x\mathbf{x} which satisfy equation (cot⁡−1x)2−3(cot⁡−1x)+2>0\left(\cot ^{-1} x\right)^{2}-3\left(\cot ^{-1} x\right)+2>0 is x<x< cot⁡a\cot a or x>cot⁡bx>\cot b Find the value of a+ba+b
Q6MathsUnit 14: Trigonometry
ln⁡ΔABC,BC=AB\ln \Delta A B C, B C=A B and ∠B=80∘\angle B=80^{\circ} Then ∠A\angle A is equal to
Q7MathsUnit 14: Trigonometry
Two line segments ABA B and ACA C include an angle of 60060^{0} where AB=5cmA B=5 \mathrm{cm} and ACA C =7cm.=7 \mathrm{cm} . Locate points P\mathrm{P} and Q\mathrm{Q} on AB\mathrm{AB} and AC,A C, respectively such that AP=34A P=\frac{3}{4} ABA B and AQ=14AC.A Q=\frac{1}{4} A C . Join PP and QQ and measure the length PQ.
Q8MathsUnit 14: Trigonometry
Statement I: The equation (sin⁡−1x)3+(cos⁡−1x)3−aπ3=0\left(\sin ^{-1} x\right)^{3}+\left(\cos ^{-1} x\right)^{3}-a \pi^{3}=0 has solution for all a⩾132a \geqslant \frac{1}{32} Statement II : For any xϵR,sin−1x+\boldsymbol{x} \boldsymbol{\epsilon} \boldsymbol{R}, \boldsymbol{s} \boldsymbol{i n}^{-1} \boldsymbol{x}+ cos⁡−1x=π2\cos ^{-1} x=\frac{\pi}{2} and 0≤(sin⁡−1x−π4)2≤0 \leq\left(\sin ^{-1} x-\frac{\pi}{4}\right)^{2} \leq 9π216\frac{9 \pi^{2}}{16}
Q9MathsUnit 14: Trigonometry
The terminal arm is in II quadrant, what are the measures of possible angles?
Q10MathsUnit 14: Trigonometry
If tan⁡θ=xsin⁡ϕ1−xcos⁡ϕ,tan⁡ϕ=\tan \theta=\frac{x \sin \phi}{1-x \cos \phi}, \tan \phi= ysin⁡θ1−ycos⁡θ,\frac{y \sin \theta}{1-y \cos \theta}, then xy=\frac{x}{y}=
Q11MathsUnit 14: Trigonometry
If 1−sin⁡A1+sin⁡A+sin⁡Acos⁡A=1cos⁡A,\sqrt{\frac{1-\sin A}{1+\sin A}}+\frac{\sin A}{\cos A}=\frac{1}{\cos A}, for all permissible values of A,A, then AA belongs to This question has multiple correct options
Q12MathsUnit 14: Trigonometry
If two triangles are −−−_{--}- they are similar.
Q13MathsUnit 14: Trigonometry
Assertion (A)(A) If 0<x<π20<x<\frac{\pi}{2} then sin⁡−1(cos⁡x)+cos⁡−1(sin⁡x)=π−2x\sin ^{-1}(\cos x)+\cos ^{-1}(\sin x)=\pi-2 x Reason (R)cos⁡−1x=π2−sin⁡−1x∀x∈(\mathrm{R}) \cos ^{-1} x=\frac{\pi}{2}-\sin ^{-1} x \forall x \in [0,1][\mathbf{0}, \mathbf{1}]
Q14MathsUnit 14: Trigonometry
Assertion fi=12nsin⁡−1xi=nπ∀nϵNf_{i=1}^{2 n} \sin ^{-1} x_{i}=n \pi \forall n \epsilon N then ∑i=12nxi=\sum_{i=1}^{2 n} x_{i}= ∑i=12nxi2=∑i=12nxin=2n\sum_{i=1}^{2 n} x_{i}^{2}=\sum_{i=1}^{2 n} x_{i}^{n}=2 n Reason −π2≤sin⁡−1x≤π2∀xϵ[−1,1]-\frac{\pi}{2} \leq \sin ^{-1} x \leq \frac{\pi}{2} \forall x \epsilon[-1,1]
Q15MathsUnit 14: Trigonometry
What is the length of arc AB making angle of 1260126^{0} at center of radius 8?8 ?

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