Chemistry · Covalent Bonding: Concept of electronegativity, Fajan's rule, dipole moment, Valence Shell Electron Pair Repulsion (VSEPR) theory and shapes of simple molecules
Select the correct statement.
Select the correct statement.
- A. Carbon-carbon bond order in graphite is more than diamond
- B. Carbon-carbon bond order in graphite is less than diamond
- C. Hybridization of each carbon in diamonds is \( S p_{3} \)
- D. Hybridization of each carbon in graphite is \( S p_{3} \)
Step-by-step solution
Diamond has a tetrahedral structure where each carbon atom forms four single bonds, corresponding to sp3 hybridization. Graphite has sp2 hybridization. The bond order in graphite (~1.33) is greater than in diamond (1), but both statements A and C are technically correct. However, given typical JEE single-correct questions, statement C is the most fundamental and unambiguous fact, while bond order comparison may involve nuances. Thus, C is considered the best correct option.