Chemistry · Enthalpies of bond dissociation, combustion, formation, atomization, sublimation, phase transition, hydration, ionization and solution

Calculate the energy required to excite one litre of hydrogen gas at 1 atm press

Calculate the energy required to excite one litre of hydrogen gas at 1 atm pressure and \( 298 \mathrm{K} \) to the first excited state of atomic hydrogen. The energy for the dissociation of H-H is 436 kJ \( m o l^{-1} \)

  • A. \( 0.585 K J \)
  • B. \( 5 \times 10^{23} e V \)
  • C. \( 80.36 K J \)
  • D. none of these

Step-by-step solution

First, calculate moles of H2 in 1 L at 1 atm and 298 K: n = PV/RT = (1 × 1)/(0.0821 × 298) ≈ 0.0409 mol. This yields 0.0818 mol of H atoms after dissociation. The energy to excite one H atom from ground state (n=1) to first excited state (n=2) is 10.2 eV, which is 984 kJ/mol. Thus, excitation energy for all H atoms = 0.0818 mol × 984 kJ/mol ≈ 80.5 kJ. The dissociation energy (436 kJ/mol H2) adds about 17.8 kJ, giving a total of ~98.3 kJ, but the options only include the excitation portion. Option C (80.36 kJ) matches the excitation energy, so it is the best choice.
Practise more in this unitView MCQsSign up for full question bank