Chemistry · s, p, d and f block elements
Read the following passage and answer the questions at the end of it. Dilute sol
Read the following passage and answer the questions at the end of it. Dilute solution of alkali metals in liquied \( N H_{3} \) is blue. It is the ammoniated electron which is responsible for the blue color of the solution and the electrical conductivity is due to the ammoniated cation, \( \left[\boldsymbol{M}\left(\boldsymbol{N} \boldsymbol{H}_{3}\right)_{x}\right]^{+} \) as well as the ammoniated electron, \( \left[e\left(N H_{3}\right)_{y}\right]^{-} \) values of \( x \) and \( y \) depend on the extent of solvation \( \left(b y N H_{3}\right) . \) Dilute solutions are paramagnetic due to free electrons. What happens if alkali metal is allowed to react with concentrated ammonia solution?
- A. Paramagnetic character of solvated electrons is retained
- B. Solvated electrons associate to form electron-pairs and paramagnetic character decreases
- C. Reducing character is increased
- D. Reducing character is not affected
Step-by-step solution
In concentrated ammonia solutions, alkali metal solvated electrons pair up to form diamagnetic electron pairs (like [e(NH3)y]2-), reducing paramagnetism. This is a well-known phenomenon in alkali metal-ammonia solutions.
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