Chemistry · Ionization of water, pH scale, common ion effect, hydrolysis of salts and pH of their solutions, the solubility of sparingly soluble salts, solubility products and buffer solutions
100ml of a solution of HCl with pH value 3 is diluted with of water. The new pH
100ml of a solution of HCl with pH value 3 is diluted with \( 400 \mathrm{ml} \) of water. The new pH of the solution is?
- A. 3.7
- B. 5.3
- C. 4.2
- D. 5.6
Step-by-step solution
Initial [H+] = 10^{-3} M from pH = 3. Moles H+ = 0.1 L × 10^{-3} M = 10^{-4} mol. After dilution to 500 mL = 0.5 L, new [H+] = 10^{-4} / 0.5 = 2×10^{-4} M. pH = -log(2×10^{-4}) = 4 - log2 ≈ 3.7.
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