Chemistry · Equilibrium involving chemical processes: Law of chemical equilibrium, equilibrium constants (Kp and Kc) and their significance, the significance of Delta G and Delta G° in chemical equilibrium

For the following equilibrium, in gaseous phase, is of the total volume when equ

For the following equilibrium, \( N_{2} O_{4} \rightleftharpoons \) \( 2 N O_{2} \) in gaseous phase, \( N O_{2} \) is \( 50 \% \) of the total volume when equilibrium is set up. Hence, percent of dissociation of \( N_{2} O_{4} \) is:

  • A. 50\%
  • B. 25\%
  • C. \( 66.66 \% \)
  • D. 33.33\%

Step-by-step solution

Let initial moles of N2O4 be 1. Let α be the degree of dissociation. At equilibrium: N2O4 = 1-α, NO2 = 2α, total moles = 1+α. Given NO2 is 50% of total volume (mole fraction = 0.5), so 2α/(1+α) = 0.5. Solving gives α = 1/3 = 33.33%.
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