Chemistry · Alkanes: Conformations: Sawhorse and Newman projections (of ethane), mechanism of halogenation of alkanes
Arrange the following hydrocarbons in the increasing order of volume of oxygen r
Arrange the following hydrocarbons in the increasing order of volume of oxygen required for complete combustion per mole under the same conditions. (a) Ethane (b) Propyne (c) Ethyne (d) Propene (e) Propane (f) Ethene
- A. \( c<f<a<b<d<e \)
- B. \( e<d<b<a<f<c \)
- C. \( c<b<f<d<a<e \)
- D. \( e<b<d<f<a<c \)
Step-by-step solution
For complete combustion, moles of O2 per mole of hydrocarbon = x + y/4. Ethyne (C2H2): 2.5; Ethene (C2H4): 3; Ethane (C2H6): 3.5; Propyne (C3H4): 4; Propene (C3H6): 4.5; Propane (C3H8): 5. Increasing order: ethyne < ethene < ethane < propyne < propene < propane, which matches option A.
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