Chemistry · Electrolytic and metallic conduction, conductance in electrolytic solutions, molar conductivities and their variation with concentration, Kohlrausch's law and its applications
The amount of electricity that can deposit of silver from silver nitrate solutio
The amount of electricity that can deposit \( 108 g \) of silver from silver nitrate solution is:
- A. 1 ampere
- B. 1 coulomb
- C. 1 Faraday
- D. 2 ampere
Step-by-step solution
The atomic mass of silver is 108 g/mol, so 108 g corresponds to 1 mole of Ag. The reduction half-reaction is Ag⁺ + e⁻ → Ag, meaning 1 mole of electrons is required to deposit 1 mole of silver. 1 mole of electrons equals 1 Faraday (≈96500 C). Thus, the required amount of electricity is 1 Faraday.
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