Chemistry · Electrochemical cells: Electrolytic and Galvanic cells, different types of electrodes, electrode potentials including standard electrode potential, half-cell and cell reactions
What is the electric current required to deposit 0.972 g of chromium in three ho
What is the electric current required to deposit 0.972 g of chromium in three hours? (E.C.E. of chromium is 0.00018 g/c)
- A. \( 0.50 A \)
- B. 1A
- C. zero
- D. 2.5A
Step-by-step solution
Using the formula m = E.C.E. × I × t, where m = 0.972 g, E.C.E. = 0.00018 g/C, and t = 3 hours = 10800 s. Solving for I: I = 0.972 / (0.00018 × 10800) = 0.972 / 1.944 = 0.5 A.