Chemistry · Electronic concepts of oxidation and reduction, redox reactions, oxidation number, rules for assigning oxidation number and balancing of redox reactions
Which statement(s) is/are not correct about the reaction? +\boldsymbol{2} \bolds
Which statement(s) is/are not correct about the reaction? \( \boldsymbol{H}_{2} \boldsymbol{O}_{2}(\boldsymbol{a} \boldsymbol{q})+\boldsymbol{2} \boldsymbol{I}^{-}(\boldsymbol{a} \boldsymbol{q})+\boldsymbol{2} \boldsymbol{H}^{+}(\boldsymbol{a} \boldsymbol{q}) \rightarrow \) \( \boldsymbol{I}_{2}(\boldsymbol{a} \boldsymbol{q})+\boldsymbol{2} \boldsymbol{H}_{2} \boldsymbol{O}(l) \boldsymbol{I}_{2}(\boldsymbol{a} \boldsymbol{q})+ \) \( \mathbf{2} N a_{2} S_{2} O_{3} \rightarrow N a_{2} S_{4} O_{6}+2 N a I ? \) This question has multiple correct options
- A. The \( I_{2} \) formed is consumed completely in the second state is confirmed by addition of starch just before its complete consumption
- B. The reaction process is called clock reaction because the appearance of blue colour on addition of starch is like an alarm given by clock
- C. Sulphur is oxidised whereas iodine is oxidised and reduced during whole process
- D. \( H_{2} O_{2} \) acts as reducing agent
Step-by-step solution
In the reaction H2O2 + 2I- + 2H+ → I2 + 2H2O, H2O2 is reduced (oxygen goes from -1 to -2), thus it acts as an oxidizing agent, not a reducing agent. Therefore, statement D is incorrect.
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