Chemistry · The vapour pressure of solutions and Raoult's Law - Ideal and non-ideal solutions, vapour pressure composition, plots for ideal and non-ideal solutions
Pick out the correct statements This question has multiple correct options
Pick out the correct statements This question has multiple correct options
- A. The ratio of vapour pressure over solution phase on mixing two immiscible liquids is equal to ratio of their moles in vapour phase
- B. The ratio of vapour pressure over solution phase on mixing two miscible liquids is equal to ratio of their moles in liquid phase
- C. The ratio of vapour pressure over solution phase on mixing two miscible liquids is equal to ratio of the product of their vapour pressure and their moles fraction in a liquid phase
- D. The ratio of vapour pressure over solution phase on mixing two miscible liquids is equal to ratio of the product of their vapour pressure and their mole fraction in vapour phase
Step-by-step solution
For ideal miscible liquids, Raoult's law states that the partial pressure of component A is p_A = x_A * p_A^o, where x_A is the mole fraction in the liquid phase and p_A^o is the vapour pressure of pure A. Similarly, p_B = x_B * p_B^o. Thus, the ratio of their partial pressures (vapour pressure over solution) is p_A/p_B = (x_A p_A^o)/(x_B p_B^o), which is exactly the ratio of the product of their vapour pressure and mole fraction in the liquid phase. Options B and D are incorrect because the ratio of partial pressures is not equal to the ratio of mole fractions in the liquid phase (unless p_A^o = p_B^o) nor the ratio of the product of vapour pressure and mole fraction in the vapour phase. Option A is correct for immiscible liquids but not related to miscible liquids.
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