Chemistry · Mole concept, molar mass, percentage composition, empirical and molecular formulae
An oxide of metal M has by mass of oxygen. Metal M has atomic mass of 24. The em
An oxide of metal M has \( 40 \% \) by mass of oxygen. Metal M has atomic mass of 24. The empirical formula of the oxide:
- A. \( M_{2} O \)
- B. \( M_{2} O_{3} \)
- C. \( M O \)
- D. \( M_{3} O_{4} \)
Step-by-step solution
Given 40% oxygen by mass, the metal M (atomic mass 24) accounts for 60%. For an empirical formula M_x O_y, the mass ratio gives: (16y)/(24x+16y)=0.4 → 16y = 9.6x + 6.4y → 9.6y = 9.6x → x=y. Thus the empirical formula is MO.
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