Chemistry · Chemical equations and stoichiometry
heated together, the maximum weight of gas evolved will be:
heated together, the maximum weight of \( C l_{2} \) gas evolved will be:
- A. 2 gm
- B. 0.975 gm
- C. \( 0.486 \mathrm{gm} \)
- D. 0.972 gm
Step-by-step solution
The maximum weight of Cl₂ gas evolved is calculated based on the reaction MnO₂ + 4HCl → MnCl₂ + Cl₂ + 2H₂O. Assuming 2 g each of MnO₂ and HCl, HCl is the limiting reagent. Moles of HCl = 2 g / 36.5 g/mol ≈ 0.0548 mol, yielding 0.0548/4 = 0.0137 mol Cl₂. Mass of Cl₂ = 0.0137 mol × 71 g/mol ≈ 0.972 g.
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