Chemistry · Mole concept, molar mass, percentage composition, empirical and molecular formulae
of a gas at of weight the mol.wt.of gas is:
\( 380 \mathrm{mL} \) of a gas at \( 27^{0} \mathrm{C}, 800 \mathrm{mm} \) of \( \mathrm{Hg} \) weight \( 0.455 \mathrm{g} . \) the mol.wt.of gas is:
- A. 27
- B. 28
- C. 29
- D. 30
Step-by-step solution
Use ideal gas law: PV = nRT. Convert V=0.380 L, T=300 K, P=800/760=1.0526 atm. n = PV/(RT) = (1.0526×0.380)/(0.0821×300) = 0.400/24.63 = 0.01624 mol. Molar mass = mass/n = 0.455/0.01624 = 28.0 g/mol.
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