Chemistry · Chemical equations and stoichiometry
of is mixed with air having 20 per cent by volume. What would be the final volum
\( 10 \mathrm{ml} \) of \( \mathrm{CO} \) is mixed with \( 25 \mathrm{ml} \) air having 20 per cent \( O_{2} \) by volume. What would be the final volume if none of \( \mathrm{CO} \) and \( O_{2} \) is left after the reaction?
- A. 30 \( m 1 \)
- B. 40 \( m \)
- C. \( 43 \mathrm{ml} \)
- D. 49 \( m \)
Step-by-step solution
Air contains 20% O2 by volume, so 25 ml air has 5 ml O2. The reaction 2CO + O2 → 2CO2 shows that 10 ml CO requires 5 ml O2 to completely react, producing 10 ml CO2. The remaining 20 ml N2 from air is inert. Total final volume = 10 ml CO2 + 20 ml N2 = 30 ml.
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