Chemistry · Chemical equations and stoichiometry
When the same amount of zinc is treated separately with excess of sulphuric acid
When the same amount of zinc is treated separately with excess of sulphuric acid and excess of sodium hydroxide, the ratio of volumes of hydrogen evolved is
- A. 1: 1
- B. 1: 2
- C. 2: 1
- D. 9: 4
Step-by-step solution
Zinc reacts with excess sulphuric acid: Zn + H2SO4 → ZnSO4 + H2. With excess sodium hydroxide: Zn + 2NaOH → Na2ZnO2 + H2. Both reactions produce one mole of hydrogen per mole of zinc. Hence the volume ratio is 1:1.
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