Maths · Circle, conic sections: A standard form of equations of a circle, the general form of the equation of a circle, its radius and centre

In the figure, an equilateral triangle of side and its circumcircle is shown Fin

In the figure, an equilateral triangle of side \( 6 \mathrm{cm} \) and its circumcircle is shown Find the area of shaded portion. Take \( (\boldsymbol{\pi}=\mathbf{3 . 1 4}, \sqrt{\mathbf{3}}=\mathbf{1 . 7 3}) \)

  • A. \( 22.11 \mathrm{cm}^{2} \)
  • B. \( 22 \mathrm{cm}^{2} \)
  • C. \( 21.11 \mathrm{cm}^{2} \)
  • D. \( 23.11 \mathrm{cm}^{2} \)

Step-by-step solution

The circumradius of an equilateral triangle with side 6 cm is R = a/√3 = 6/√3 = 2√3 cm. Using √3 = 1.73, R = 3.46 cm. Area of circumcircle = πR² = 3.14 × (3.46)² = 3.14 × 11.9716 = 37.58 cm² (more precisely, 12π = 37.68 cm²). Area of equilateral triangle = (√3/4) × a² = (1.73/4) × 36 = 1.73 × 9 = 15.57 cm² (more precisely, 9√3 = 15.57 cm²). Shaded area = area of circle - area of triangle = 37.68 - 15.57 = 22.11 cm².
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