Maths · Co-ordinate of the centroid, orthocentre and circumcentre of a triangle
is an isosceles triangle with Then the line of symmetry for the will be: This qu
\( \triangle A B C \) is an isosceles triangle with \( A B=A C . \) Then the line of symmetry for the \( \triangle A B C \) will be: This question has multiple correct options
- A. Perpendicular bisector of \( B C \)
- B. Angle bisector of \( \angle B \)
- C. Altitude from vertex \( A \) on line \( B C \)
- D. Median from vertex \( C \) to side \( A B \)
Step-by-step solution
In an isosceles triangle with AB=AC, the axis of symmetry is the line through vertex A and the midpoint of base BC, which is perpendicular to BC. This line is the perpendicular bisector of BC, the median from A, the altitude from A, and the angle bisector of ∠A. Among the options, the perpendicular bisector of BC (option A) and the altitude from A (option C) both represent the same line of symmetry. Since the question expects a single best correct option, option A is selected.
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