Maths · Quadratic equations in real and complex number systems and their solutions
Find the root of the quadratic equation by using the quadratic formula
Find the root of the quadratic equation \( x^{2}+2 \sqrt{2 x}+6=0 \) by using the quadratic formula
- A. \( x=\sqrt{2} \pm 2 i \)
- B. \( x=-\sqrt{2} \pm 2 i \)
- C. \( x=-\sqrt{4} \pm 2 i \)
- D. \( x=-\sqrt{2} \pm 4 i \)
Step-by-step solution
Given quadratic: x² + 2√2 x + 6 = 0. Using quadratic formula: x = [-b ± √(b² - 4ac)] / (2a) with a=1, b=2√2, c=6. Compute discriminant: b² - 4ac = (2√2)² - 4·1·6 = 8 - 24 = -16. √(-16) = 4i. Then x = [-2√2 ± 4i] / 2 = -√2 ± 2i.
Related MCQs
- A family is going to a theme park having members in the family. Each ticket costs and the number of tickets needs to be bought can be calcul…
- Determine the nature of roots of the equation…
- Determine whether the equation is quadratic or not.…
- The produce of a square field when sold at the rate of Rs. 1.50 per 100 sq. metres fetches Rs. What will be the cost of putting a fence all …
- What are the solution(s) to the system of equations and…