Maths · Limits, continuity and differentiability
The function =\boldsymbol{e}^{-|\boldsymbol{x}|} \) is
The function \( \boldsymbol{f}(\boldsymbol{x})=\boldsymbol{e}^{-|\boldsymbol{x}|} \) is
- A. continuous everywhere but not differentiable at \( x=0 \)
- B. continuous and differentiable everywhere
- C. not continuous at \( x=0 \)
- D. None of the above
Step-by-step solution
The function f(x)=e^{-|x|} is piecewise: for x≥0, f(x)=e^{-x}; for x<0, f(x)=e^{x}. Both pieces are continuous and differentiable on their domains. At x=0, f(0)=1, left-hand limit = lim_{x→0-} e^{x}=1, right-hand limit = lim_{x→0+} e^{-x}=1, so continuous. Left derivative = e^{0}=1, right derivative = -e^{0}=-1, not equal, thus not differentiable at x=0.
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