A 5 digit number divisible by 3 is to be formed using the numerals 0,1,2,3,4 \&

The digits are 0,1,2,3,4,5. Sum = 15, divisible by 3. For a 5-digit number with 5 different digits, sum of its digits = 15 - excluded digit. To be divisible by 3, excluded digit must be 0 or 3. Case exclude 0: digits {1,2,3,4,5}, permutations = 5! = 120. Case exclude 3: digits {0,1,2,4,5}, total permutations = 5! = 120, but those starting with 0 are invalid: 4! = 24, so valid = 120-24 = 96. Total = 120+96 = 216.