Maths · Functions
A man gives of his money to his children and of the remaining to a trust. If he
A man gives \( 40 \% \) of his money to his children and \( 20 \% \) of the remaining to a trust. If he is still left with \( \mathrm{Rs} .9,600 \) then what did he originally have?
- A. Rs.14, 000
- B. Rs.19, 845
- C. Rs.20, 000
- D. Rs.25, 409
Step-by-step solution
Let original amount be x. After giving 40% to children, remaining = 0.6x. Then gives 20% of that to trust, so remaining = 0.6x - 0.2*0.6x = 0.48x. This equals 9600, so x = 9600 / 0.48 = 20000.
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