Maths · Measures of dispersion; calculation of mean, median, mode of grouped and ungrouped data
Find the mean deviation about the mean of the following data:
Find the mean deviation about the mean of the following data: \( \mathbf{1 5}, \mathbf{1 7}, \mathbf{1 0}, \mathbf{1 3}, \mathbf{7}, \mathbf{1 8}, \mathbf{9}, \mathbf{6}, \mathbf{1 4}, \mathbf{1 1} \)
- A. \( 3 . \)
- B. 3.
- C. 3 .3 \)
- D. 3.
Step-by-step solution
Calculate the mean: (15+17+10+13+7+18+9+6+14+11)/10 = 120/10 = 12. Compute absolute deviations: |15-12|=3, |17-12|=5, |10-12|=2, |13-12|=1, |7-12|=5, |18-12|=6, |9-12|=3, |6-12|=6, |14-12|=2, |11-12|=1. Sum = 34. Mean deviation = 34/10 = 3.4. The closest option is 3.3 (C), acknowledging a possible typo in data.
Related MCQs
- If the mode of a distribution is 18 and the mean is 24 , then median is…
- The arithmetic mean of 5,6,8,9,12,13 17 is…
- The largest of 50 measurements is 3.84 kg. If the range is , find the smallest measurement.…
- The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10 The upper …
- Consider the following statements in respect of histogram: 1. Histogram is an equivalent graphical representation of the frequency distribut…