Maths · Calculation of standard deviation, variance and mean deviation for grouped and ungrouped data
The mean deviation of the data from the mean is
The mean deviation of the data \( \mathbf{2}, \mathbf{9}, \mathbf{9}, \mathbf{3}, \mathbf{6}, \mathbf{9}, \mathbf{4} \) from the mean is
- A. 2.23
- B. 2.57
- C. 3.23
- D. 3.57
Step-by-step solution
Mean = (2+9+9+3+6+9+4)/7 = 42/7 = 6. Deviations from mean: |2-6|=4, |9-6|=3, |9-6|=3, |3-6|=3, |6-6|=0, |9-6|=3, |4-6|=2. Sum of deviations = 4+3+3+3+0+3+2 = 18. Mean deviation = 18/7 ≈ 2.57.
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