Physics · Bohr model, energy levels, hydrogen spectrum
A ion is in its first excited state. Its ionization energy is?
A \( H e^{+} \) ion is in its first excited state. Its ionization energy is?
- A. 6 .04 ev
- B. 13.60 ev
- C. 54.40 ev
- D. 48.36 ev
Step-by-step solution
For a hydrogen-like ion, energy levels are given by E_n = -13.6 Z^2 / n^2 eV. For He+ (Z=2), first excited state n=2 gives E_2 = -13.6 * 4 / 4 = -13.6 eV. Ionization energy to remove the electron to infinity is 0 - E_2 = 13.6 eV.
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