Physics · Composition and size of nucleus, atomic masses, mass-energy relation, mass defect
A nucleus with atomic number and neutron number N undergoes two decay processes.
A nucleus with atomic number \( z \) and neutron number N undergoes two decay processes. The result is a nucleus with atomic number Z-3 and neutron number N-1. Which decay processes took place?
- A. Two \( \beta^{-} \) decays
- B. Two \( \beta^{+} \) decays
- C. \( A n \alpha-d e c a y \) and \( a \beta^{-} \) decay
- D. An \( \alpha- \) decay and a \( \beta^{+} \) decay
Step-by-step solution
An α-decay reduces atomic number by 2 and neutron number by 2. A β+ decay reduces atomic number by 1 and increases neutron number by 1. Combining these: ΔZ = -2 -1 = -3, ΔN = -2 +1 = -1, matching the given changes. Thus, the processes are one α-decay and one β+ decay.
Related MCQs
- If there are nuclear particles in a nucleus of radius then the number of nuclear particles in radius will be…
- Statement A: Density of nucleus is independent of its mass number Statement B: Beryllium is used as a moderator in nuclear reactors…
- Starting with a sample of pure of its decays into in 15 min. The corresponding half-life is…
- The missing particle in the reaction:…
- Consider two nuclei of the same radioactive nuclide. One of the nuclei was created in a supernova explosion 5 billion years ago. The probabi…