Physics · Alpha-particle scattering experiment, Rutherford's model of atom
Calculate the electrostatic potential energy at the instant when the alpha parti
Calculate the electrostatic potential energy at the instant when the alpha particle stops?
- A. \( 36.3 \mathrm{MeV} \)
- B. 45.0 MeV
- C. \( 3.63 \mathrm{MeV} \)
- D. 40.0 Mev
Step-by-step solution
In the Rutherford alpha-particle scattering experiment, an alpha particle approaches a gold nucleus and is repelled electrostatically. At the point of closest approach (when it stops momentarily), its initial kinetic energy is completely converted into electrostatic potential energy. For typical experimental parameters, this potential energy is approximately 3.63 MeV. This value is commonly used in such problems.
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