Physics · Kirchhoff's laws and their applications, Wheatstone bridge, Metre Bridge
Four conductors of resistance 4,3,9 and 6 ohm are connected in and DA arms of a
Four conductors of resistance 4,3,9 and 6 ohm are connected in \( A B, B C, C D \) and DA arms of a Wheatstone bridge. The bridge can be balanced by connecting.
- A. \( 1) 6 \) ohm in series with 3 ohm conductor
- B. 2) 4 ohm in parallel with 6 ohm conductor
- C. 3 ) 3 ohm in series with 3 ohm conductor
- D. 4 ) 5 ohm in series with 6 ohm conductor
Step-by-step solution
The Wheatstone bridge is balanced when the product of resistances of opposite arms are equal. Initially, (AB)(CD) = 4*9 = 36 and (BC)(DA) = 3*6 = 18, which are not equal. Option C adds a 3-ohm resistor in series with the 3-ohm conductor in arm BC, making it 6 ohms. Then (AB)(CD) = 4*9 = 36 and (BC)(DA) = 6*6 = 36, satisfying the balance condition.
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