In a battery five dry cells each of 1.5 volt have internal resistance of 0.2,0.3,0.4,0.5 and are present in series. The battery is connected to a resistance. Identify the correct statement \)

Physics · Internal resistance, potential difference and emf of a cell, a combination of cells in series and parallel

In a battery five dry cells each of 1.5 volt have internal resistance of 0.2,0.3

In a battery five dry cells each of 1.5 volt have internal resistance of 0.2,0.3,0.4,0.5 and \( 0.6 \Omega \) are present in series. The battery is connected to a \( 1 \Omega \) resistance. Identify the correct statement \( (s) \)

A. Current in the circuit will be \( 2.5 A \)
B. Current in the circuit will be \( 1.5 A \)
C. on short circuiting the battery 3.75 d current will flow
D. Both \( (A) \) and \( (C) \)

Step-by-step solution

The total emf of five 1.5 V cells in series is 7.5 V. The total internal resistance is the sum: 0.2 + 0.3 + 0.4 + 0.5 + 0.6 = 2.0 Ω. With a 1 Ω external resistor, total resistance is 3 Ω, so current = 7.5/3 = 2.5 A (statement A correct). When short-circuited (external resistance = 0), current = 7.5/2.0 = 3.75 A (statement C correct). Hence both A and C are correct, so D is the correct option.

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Step-by-step solution

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