Physics · Einstein's photoelectric equation, particle nature of light
Threshold wavelength of tungsten is 2300 angstrom. If ultraviolet light of wavel
Threshold wavelength of tungsten is 2300 angstrom. If ultraviolet light of wavelength 1800 angstrom is incident on it, then the maximum kinetic energy of photoelectrons would be?
- A. 1.5 ev
- B. 2.5ev
- C. 3.0 ev
- D. \( 5.0 \mathrm{eV} \)
Step-by-step solution
Using the photoelectric equation: KEmax = hc(1/λ - 1/λ₀). With hc = 12400 eV·Å, λ = 1800 Å, λ₀ = 2300 Å, KEmax = 12400 × (1/1800 - 1/2300) = 12400 × (500/4140000) ≈ 1.5 eV.
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