Physics · Electromagnetic induction: Faraday's law, induced emf and current, Lenz's law, eddy currents, self and mutual inductance
A circular disc of radius 0.2 meter is placed in a uniform magnetic field of in
A circular disc of radius 0.2 meter is placed in a uniform magnetic field of \( \frac{1}{\pi} \) \( \boldsymbol{w} \boldsymbol{b} / \boldsymbol{m}^{2} \) in such way that its axis makes an angle of \( 60^{\circ} \) with \( \vec{B} \). The magnetic flux linked with the disc is?
- A. 0.08 wb
- B. 0.01 wb
- C. 0 .02 \mathrm{wb} \)
- D. 0.06 wb
Step-by-step solution
Magnetic flux Φ = B·A = B A cosθ. Given B = 1/π T, A = πr² = π(0.2)² = 0.04π m², θ = 60° (angle between B and normal to disc). So Φ = (1/π)*0.04π*cos60° = 0.04*0.5 = 0.02 Wb.
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