Physics · AC generator and transformer

A power transmission line feeds input power to a step-down transformer with its

A power transmission line feeds input power \( t 2300 \mathrm{V} \) to a step-down transformer with its primary windings having 4000 turns. The output power is delivered at \( 230 \mathrm{V} \) by the transformer. If the current in the primary of the transformer is \( 5 \mathrm{A} \) and its efficiency is \( 90 \%, \) the output current would be :

  • A. 25 A
  • B. 50 A
  • C. 35 \mathrm{A} \)
  • D. 45 A

Step-by-step solution

Input power = Vp * Ip = 2300 V * 5 A = 11500 W. Output power = efficiency * input power = 0.9 * 11500 = 10350 W. Output current = Pout / Vout = 10350 / 230 = 45 A.
Practise more in this unitView MCQsSign up for full question bank