Physics · Alternating currents, peak and RMS value of alternating current/voltage
A steady current of magnitude and an current of peak value are allowed to pass t
A steady current of magnitude \( I \) and an \( A C \) current of peak value \( I \) are allowed to pass through identical resistor for the same time. The ratio of heat produced in the two resistors will be :
- A. 2: 1
- B. 1: 2
- C. 1: 1
- D. None of these
Step-by-step solution
For steady current I, heat produced = I^2Rt. For AC with peak value I, RMS value = I/√2, so heat = (I/√2)^2 Rt = I^2Rt/2. Ratio = I^2Rt : I^2Rt/2 = 2:1.
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