In an oscillating circuit in which the maximum potential across the capacitor during the oscillations is and the maximum current through the inductor is How much time does the charge on the capacitor take to rise from zero to its maximum value?

Physics · Electromagnetic induction: Faraday's law, induced emf and current, Lenz's law, eddy currents, self and mutual inductance

In an oscillating circuit in which the maximum potential across the capacitor du

In an oscillating \( L-C \) circuit in which \( C=4.00 \mu F, \) the maximum potential across the capacitor during the oscillations is \( 1.50 V \) and the maximum current through the inductor is \( 50.0 m A \) How much time does the charge on the capacitor take to rise from zero to its maximum value?

A. \( 0.238 \mathrm{ms} \)
B. \( 0.788 \mathrm{ms} \)
C. \( 0.488 \mathrm{ms} \)
D. \( 0.188 \mathrm{ms} \)

Step-by-step solution

The time for charge to rise from zero to maximum is one-quarter of the oscillation period. Use energy conservation to find L: (1/2)CV_max^2 = (1/2)LI_max^2 → L = C V_max^2 / I_max^2 = 3.6 mH. Angular frequency ω = 1/√(LC) ≈ 8333 rad/s. Period T = 2π/ω ≈ 0.754 ms, so T/4 ≈ 0.188 ms.

Practise more in this unit View MCQs Sign up for full question bank

Step-by-step solution

Related MCQs