Physics · Reactance and impedance, LCR series circuit, resonance, power in AC circuits, wattless current
In the circle shown and They are connected in series with a.c. source as shown.W
In the circle shown \( \boldsymbol{L}=\mathbf{1} \boldsymbol{\mu} \boldsymbol{H}, \boldsymbol{C}=\mathbf{1} \boldsymbol{\mu} \boldsymbol{F} \) and \( R=1 k \Omega . \) They are connected in series with a.c. source \( V=V_{0} \sin \omega t \) as shown.Which of the following option is/are correct? This question has multiple correct options
- A. The frequency at which the current will be in the phase with the voltage is independent of \( R \)
- B. At \( \omega \sim 0 \) the current flowing through the circuitt becomes nearly zero
- C. \( A t \omega>>10^{6} r a d . s^{-1}, \) the circuit behave like a capacitor
- D. The current will be in phase with the voltage if \( \omega= \) \( 10^{4} r a d \cdot s^{-1} \)
Step-by-step solution
In a series RLC circuit, the condition for current to be in phase with voltage is resonance, which occurs at angular frequency ω₀ = 1/√(LC). This frequency depends only on L and C, not on R. Given L = 1 μH and C = 1 μF, ω₀ = 10⁶ rad/s, independent of R = 1 kΩ.
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