Physics · Electric charges: conservation of charge, Coulomb's law forces between two point charges, forces between multiple charges, superposition principle and continuous charge distribution
The force between two electrons when placedair is equal to 0.5 times the weight
The force between two electrons when placedair is equal to 0.5 times the weight of an electrons find the distance between two electrons (masselectron \( \left.=\mathbf{9 . 1} \times \mathbf{1 0}^{-\mathbf{3 1}} \mathbf{k g}\right) \)
- A. 7.2 m
- B. 72cm
- C. 72 m
- D. 720m
Step-by-step solution
The electrostatic force between two electrons is given by Coulomb's law: F = k e^2 / r^2. Setting this equal to half the weight of an electron (0.5 m_e g), we solve for r. Using k = 8.99e9 N·m²/C², e = 1.6e-19 C, m_e = 9.1e-31 kg, and g = 9.8 m/s², we get r ≈ 7.2 m.
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