Physics · Escape velocity, motion of a satellite, orbital velocity, time period and energy of satellite
Escape velocity from earth is 11.2km/sec. Another planet of same mass has radius
Escape velocity from earth is 11.2km/sec. Another planet of same mass has radius \( \frac{1}{4} \) times that of earth. What is the escape velocity from this planet?
- A. \( 11.2 k m / \)sec
- B. \( 44.8 k m / \)sec
- C. \( 22.4 k m / \)sec
- D. \( 5.6 k m / \)sec
Step-by-step solution
Escape velocity is given by v = sqrt(2GM/R). For the same mass M, if radius becomes R/4, then escape velocity becomes sqrt(2GM/(R/4)) = sqrt(4 * 2GM/R) = 2 * sqrt(2GM/R) = 2 * 11.2 = 22.4 km/s.
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