Physics · Law of conservation of linear momentum and its applications, equilibrium of concurrent forces
A machine gun fires 10 bullets/s, each of mass , the speed of each bullet is the
A machine gun fires 10 bullets/s, each of mass \( 10 g \), the speed of each bullet is \( 20 c m / s, \) then force of recoil is
- A. 200 dyne
- B. 2000 dyne
- C. 20 dyne
- D. None
Step-by-step solution
The force of recoil equals the rate of change of momentum. In CGS units, mass of each bullet = 10 g, velocity = 20 cm/s, so momentum per bullet = 10 × 20 = 200 g cm/s. Since 10 bullets are fired per second, the total change in momentum per second = 10 × 200 = 2000 g cm/s² = 2000 dyne. Hence, the recoil force is 2000 dyne.
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