Physics · Force and inertia, Newton's first law of motion, momentum, Newton's second Law of motion, impulse, Newton's third Law of motion
A particle of mass is made to move with uniform speed along the perimeter of a r
A particle of mass \( m \) is made to move with uniform speed \( v \) along the perimeter of a regular hexagon. The magnitude of impulse applied at each corner is:
- A. \( m v \)
- B. \( m v \sqrt{3} \)
- C. \( \frac{m v}{2} \)
- D. \( \frac{m v}{\sqrt{3}} \)
Step-by-step solution
At each corner of the hexagon, the velocity direction changes by 60° (external angle). The magnitude of change in velocity is Δv = 2v sin(30°) = v. Impulse equals change in momentum: J = m Δv = m v.
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