Physics · Force on a moving charge in uniform magnetic and electric fields

An electron accelerated by enters a magnetic field .If its velocity is . then \)

An electron accelerated by \( 200 \mathrm{V} \) enters a magnetic field .If its velocity is \( 100 \mathrm{m} / \mathrm{sec} \). then \( (\mathrm{e} / \mathrm{m}) \) for it will be: \( (\mathrm{C} / \mathrm{Kg}) \)

  • A. \( 1.75 \times 10^{10} \)
  • B. \( 1.75 \times 10^{11} \)
  • C. \( 1.75 \times 10^{9} \)
  • D. \( 1.75 \times 10^{6} \)

Step-by-step solution

The charge-to-mass ratio (e/m) for an electron is a well-known constant, approximately 1.76 × 10^11 C/kg. The given numbers (200 V and 100 m/s) are inconsistent with this constant, but the correct value among the options is B. Using the kinetic energy relation from acceleration: e/m = v²/(2V) = 100²/(2×200) = 25 C/kg, which does not match any option. Therefore, the intended answer is the accepted value.
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