Physics · Biot Savart law and its application to the current carrying circular loop
In hydrogen atom, an electron is revolving in the orbit of radius with radiation
In hydrogen atom, an electron is revolving in the orbit of radius \( 0.53 \dot{A} \) with \( 6.6 \times 10^{15} \) radiation/s. Magnetic field produced at the centre of the orbit is
- A. \( 0.125 W b / m^{2} \)
- B. \( 1.25 W b / m^{2} \)
- C. \( 12.5 W b / m^{2} \)
- D. \( 125 W b / m^{2} \)
Step-by-step solution
The magnetic field at the center of a circular loop due to current I is B = μ0 I / (2r). Here, current I = e f = 1.6×10^{-19} C × 6.6×10^{15} Hz = 1.056×10^{-3} A. Radius r = 0.53 Å = 0.53×10^{-10} m. Substituting μ0 = 4π×10^{-7} T·m/A gives B = (4π×10^{-7} × 1.056×10^{-3}) / (2 × 0.53×10^{-10}) ≈ 12.5 T.
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